Physics, asked by ravenclaw2585, 6 months ago

Two object of mass 100g. And200g are moving along the same line in the same Direction with velocity 2m/s and 1m/s they collide after collision the first body moves at velocity of1.67m/s in the same direction determine the velocity of the second body

Answers

Answered by tusharraj77123
2

Answer:

\large\mathbf\color{Brown}\underline{\underline{Question:}}

\textsf{Two object of mass 100 g and 200 g are}

\textsf{moving along the same line in the same}

\textsf{direction with velocity 2 m/s and 1 m/s.}

\textsf{They collide after collision the first}

\textsf{body moves at velocity of 1.67 m/s}

\textsf{in the same direction determine}

\textsf{the velocity of the second body.}

\large\mathbf\color{cyan}\underline{\underline{Given:}}

\textsf{Mass of the first object = 100 g}

\textsf{Mass of the second object = 200 g}

\textsf{Intial velocity of the first object = 2 m/s}

\textsf{Initial velocity of the second object = 1 m/s}

\textsf{Final velocity of the first object = 1.67 m/s}

\large\mathbf\color{green}\underline{\underline{To\:find:}}

\textsf{Final velocity of the second object}

\large\mathbf\color{blue}\underline{\underline{Taken:}}

\textsf{To find the final velocity of the second object.}

\textsf{Use this formula:}

\mapsto\bold{m1v1+m2v2=m1v3+m2v4}

\bold{Where,}

\textsf{m1=Mass of the first object}

\textsf{m2=Mass of the second object}

\textsf{v1=Initial velocity of the first object}

\textsf{v2=Initial velocity of the second object}

\textsf{v3=Final velocity of the first object}

\textsf{v4=Final velocity of the second object}

\textsf{In the following we have to find the final}

\textsf{velocity of the second object or v4}

\large\mathbf\color{magenta}\underline{\underline{Concept:}}

\textsf{Use the formula to get the final velocity of the}

\textsf{second object after the collision between the}

\textsf{first object.}

\large\mathbf\color{red}\underline{\underline{Solution:}}

\bold{Taken,}

\bold{m1v1+m2v2=m1v3+m2v4}

\Rightarrow\bold{100g×2m/s+200g×1m/s=100g×1.67+200g×v4}

\Rightarrow\bold{200+200=167+200v4}

\Rightarrow\bold{400=167+200v4}

\Rightarrow\bold{400-167=200v4}

\Rightarrow\bold{233=200v4}

\Rightarrow\bold{\frac{233}{200}=v4}

\Rightarrow\bold{1.65m/s=v4}

\small\therefore\bold{The\:final\:velocity\:of\:the\:second\:object =1.65m/s}

______________________________________

So , the final velocity of the second object after collision is 1.65 m/s.

______________________________________

\large\mathbf\color{purple}\underline{\underline{Extra\:information:}}

\bold{Velocity=\frac{Displacement}{Time}}

\bold{Acceleration=\frac{Final\:velocity-Initial\:velocity}{Time\:taken}}

HOPE IT HELPS YOU

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