Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s^-1 before the collision, during which they stick together. What will be the velocity of the combined object after collision ?
Answers
❋ Since two objects of equal masses are moving in opposite direction with equal velocity, therefore the velocity of the objects after collision during which they stick together will be zero.✔️✔️
Mass of first object,
Mass of second object,
Initial velocity of second object,
(Since second object is moving in opposite direction)
Final velocity of the objects, which stick after collision,
We know that,
Substituting the values, we get
1.5 × 2.5 + 1.5 × (-2.5) = 1.5 ×
+ 1.5 ×
3.75 - 3.75 =
(1.5 + 1.5)
Therefore, final velocity of both the objects after collision will became zero.
#Be_Brainly
ANSWER:-
Given:
Two objects, each of mass 1.5kg, are moving in the same height line in opposite directions. The velocity of each object is 2.5m/s-¹ before the collision, during which they stick together.
To find:
What will be the velocity of the time combined object after collision?
Solution:
We know that momentum formula;
=) p= mv
⏺️p= momentum
⏺️m= mass
⏺️v= velocity.
Given,
Mass of 1st object, m1= 1.5kg
Velocity of 1st object, v1= 2.5 m/s
Momentum of 1st object= m1v1
=) 1.5× 2.5
=) 3.75kg m/s
&
mass of 2nd object,m2= 1.5kg
velocity of 1st object,v2= -2.5m/s
So,
Momentum of 2nd object, m2v2
=) 1.5 × (-2.5)
=) -3.75kg m/s
So,
Total momentum= 3.75+ (-3.75)
=) 3.75 -3.75
=) 0 kg m/s.......(1)
Combined mass = m1 +m2
=) 1.5 + 1.5
=) 3.0 kg
Let, the velocity of the combined objects after collision will be v m/s.
Total momentum;
=) (m1 + m2)×v
=) 3.0 × v...........(2)
We know that,
According to the principle of conservation of momentum:
Total momentum before collision= total momentum after collision.
=) 0= 3.0 ×v
=) v= 0/3.0
=) v=0m/s
Therefore,
The velocity of the combined objects after the collision will be 0m/s.