Question

Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s^-1 before the collision, during which they stick together. What will be the velocity of the combined object after collision ? ​

Answer 1

$\huge{\pink{\green {\sf\boxed{ANSWER}}}}$

❋ Since two objects of equal masses are moving in opposite direction with equal velocity, therefore the velocity of the objects after collision during which they stick together will be zero.✔️✔️

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$\bold{\underline {</strong><strong>Given</strong><strong>:</strong><strong>}</strong><strong>}$

Mass of first object, ${</strong><strong>m1</strong><strong> </strong><strong>=</strong><strong> </strong><strong>1.5</strong><strong>\</strong><strong>:</strong><strong> </strong><strong>kg</strong><strong>}$

Mass of second object, ${</strong><strong>m2</strong><strong> = </strong><strong>2</strong><strong>.</strong><strong>5\: </strong><strong>m</strong><strong>\</strong><strong>:</strong><strong>{</strong><strong>s</strong><strong>}</strong><strong> </strong><strong>{</strong><strong>-</strong><strong>1</strong><strong>}</strong><strong>}$

Initial velocity of second object, ${</strong><strong>u2</strong><strong> = </strong><strong>-</strong><strong>2.5\: m\:{s} {-1}}$

(Since second object is moving in opposite direction)

Final velocity of the objects, which stick after collision, ${</strong><strong>v</strong><strong> =</strong><strong>?</strong><strong> </strong><strong>}$

We know that,

${</strong><strong>m1u1</strong><strong> </strong><strong>+</strong><strong> </strong><strong>m2u2</strong><strong> </strong><strong>=</strong><strong> </strong><strong>m1v1</strong><strong> </strong><strong>+</strong><strong> </strong><strong>m2v2</strong><strong>}$

Substituting the values, we get

${⟹}$1.5 × 2.5 + 1.5 × (-2.5) = 1.5 ×${</strong><strong>v</strong><strong>}$+ 1.5 × ${</strong><strong>v</strong><strong>}$

${⟹}$3.75 - 3.75 = ${</strong><strong>v</strong><strong>}$(1.5 + 1.5)

$</strong><strong>⟹</strong><strong> {</strong><strong>v</strong><strong> </strong><strong>=</strong><strong> </strong><strong>\</strong><strong>dfrac</strong><strong> </strong><strong>{</strong><strong>0</strong><strong>}</strong><strong>{</strong><strong>3.00</strong><strong>}</strong><strong>}</strong><strong> </strong><strong>=</strong><strong>{</strong><strong>\bf</strong><strong> </strong><strong>{</strong><strong>0</strong><strong>}</strong><strong>}$

Therefore, final velocity of both the objects after collision will became zero.

#Be_Brainly

Answer 2

ANSWER:-

Given:

Two objects, each of mass 1.5kg, are moving in the same height line in opposite directions. The velocity of each object is 2.5m/s-¹ before the collision, during which they stick together.

To find:

What will be the velocity of the time combined object after collision?

Solution:

We know that momentum formula;

=) p= mv

⏺️p= momentum

⏺️m= mass

⏺️v= velocity.

Given,

Mass of 1st object, m1= 1.5kg

Velocity of 1st object, v1= 2.5 m/s

Momentum of 1st object= m1v1

=) 1.5× 2.5

=) 3.75kg m/s

&

mass of 2nd object,m2= 1.5kg

velocity of 1st object,v2= -2.5m/s

So,

Momentum of 2nd object, m2v2

=) 1.5 × (-2.5)

=) -3.75kg m/s

So,

Total momentum= 3.75+ (-3.75)

=) 3.75 -3.75

=) 0 kg m/s.......(1)

Combined mass = m1 +m2

=) 1.5 + 1.5

=) 3.0 kg

Let, the velocity of the combined objects after collision will be v m/s.

Total momentum;

=) (m1 + m2)×v

=) 3.0 × v...........(2)

We know that,

According to the principle of conservation of momentum:

Total momentum before collision= total momentum after collision.

=) 0= 3.0 ×v

=) v= 0/3.0

=) v=0m/s

Therefore,

The velocity of the combined objects after the collision will be 0m/s.

Hope it helps ☺️