Question

two objects having equal masses are moving with uniform velocities of 2 m/s anf 6m/s . calculate rhe ratio of their kinetic energies...

Answer 1

hope it helps you...............

Answer 2

ANSWER
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m1 = m, 
m2 = m, 
v1 = 2v,
v2 = 3v,
EI/E2 =
We know that E = 1/2 mv^2

$\frac{e1}{e \: 2} = \frac{ \frac{1}{2} }{ \frac{1}{2} } = m \: v \: {}^{2} = \frac{v \: \frac{2}{1} }{v \: = \frac{2}{2} } = 4 = 9$
Total energy = KE + PE


Now, velocity after travelling distance h/2 is


v^2 - u^2 = 2g(h/2)


v^2 = gh

.......
KE = 1/2 mv^2 = 1/2 mgh And 
PE = 1/2 mgh 

= 1 : 9



total energy
= 1/2 mgh + 1/2 mgh = mgh