Question

two objects of masses 100 g
and 200 g
are moving along the same line and direction with velocities of 2m/s and 1m/s, respectively.
They collide and after the collision, the first object moves at a velocity of 1.67m/s. Determine the velocity of the second object.

Answer 1

Mass of one of the objects, m1 = 100 g = 0.1 kg Mass of the other object, m2 = 200 g = 0.2 kg Velocity of m1 before collision, v1 = 2 m/s Velocity of m2 before collision, v2 = 1 m/s Velocity of m1 after collision, v3 = 1.67 m/s Velocity of m2 after collision = v4 According to the law of conservation of momentum: Total momentum before collision = Total momentum after collision m1v1 + m2v2 = m1v3 + m2v4 ⇒ 0.1×2 + 0.2×1 = 0.1×1.67 + 0.2×v4 ⇒ 0.4 = 0.67 + 0.2×v4 ⇒ v4 = 1.165 m/s

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Answer 2

M1U1×M2U2=M1V1×M2V2

100×2×200×1=100×1.67×200×V2

V2=2×200×100×1÷100×1.67×200

V2=1.19