Question

• two objects of masses 100g and 200g are
moving along the same line and direction
with velocities
of 2 ms-' 1ms-' respectively. They
collide
and after the collision, the first object moves at a
velocity of 1.67ms-' Determine the
velocity of the second object​

Answer 1

Answer:

Explanation:

Saline soils usually have an EC of more than 4 mmho cm-1. Salts generally found in saline soils include NaCl (table salt), CaCl2, gypsum (CaSO4), magnesium sulfate, potassium chloride and sodium sulfate.

Answer 2

Answer:

ELLO!!

♡´･ᴗ･`♡

Explanation:

Before Collision After collision

A B A B

100 g 200g → 100g 200g

2m/s 1m/s v=? 1.67ms −1

Let the 100 g and 200 g objects be A and B .

Initial momentum of A = 100 ×2=0.2kgms−1

1000

Initial momentum of B = 200 × 1 =0.2kgms−1

1000

∴ Total momentum of A and B before collision

= 0.2+0.2=0.4kgms −1

Let the velocity of A after collision = v

∴ Momentum of A after collision =100×v =0.1v

1000

Also, momentum of B after collision =

200 × 1.67 = 0.334kgms −1

1000

∴ Total momentum of A and B after collision

=0.1×v+0.334

Using the law of conservation of momentum, momentum of A and B after collision = momentum of A and B before collision

0.1×v+0.334=0.4

0.1×v=0.4−0.334

⇒ v = 0.066 = 0.66ms −1

0.1

HOPEFULLY YOU MIGHT GET HELP FROM IT!!