Question

Two objects, one 4 times as massive as the other are approaching each other under their mutual gravitation attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/s2. When the separation between them is 25km, the acceleration of the heavier object is

Answer 1

Answer:F=Gm1m2r2m1=mm2=4mwhen r = 100 km = 100000 ma1=1 m/s2F=m1a=Gm1m2r2ma=G4m2(100)2×1064Gm =1010F2=ma2=ma2=G4m2(25)2×106a2=1010(25)2×106=16 m/

I explained well in the photo check it once..

Answer 2

Answer:

Answer is 4m/s^2

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