# Two of the angles in the polygon are each 170°. The remaining 20 angles are equal to each other. Calculate the size of one of the 20 equal angles.

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**Answer:**

Two angles of an eight sided polygon are 142

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and 176

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and the remaining angles are equal to each other. Let each equal angle = x

Sum of all interior angles of a polygon is = 180

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(n−2)=180

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(8−2)=1080

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Now,

142

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+176

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+(8−2)×x=1080

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=>6x=762

=>x=127

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Each equal angle is = 127

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