Two of the angles in the polygon are each 170°. The remaining 20 angles are equal to each other. Calculate the size of one of the 20 equal angles.
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Answer:
Two angles of an eight sided polygon are 142
o
and 176
o
and the remaining angles are equal to each other. Let each equal angle = x
Sum of all interior angles of a polygon is = 180
o
(n−2)=180
o
(8−2)=1080
o
Now,
142
o
+176
o
+(8−2)×x=1080
o
=>6x=762
=>x=127
o
Each equal angle is = 127
o
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