Math, asked by rajkumarvarshney57, 1 year ago


two opposite angles of a parallelogram are (3x-2) and (50-X). Find the measure
of each angle of the parallelogram.​

Answers

Answered by karthi77777
3

Answer:

37°,37°,143° and 143°

Step-by-step explanation:

Given,

Two opposite angles of a parallelogram are 3x-2 and 50-x.

In a parallelogram opposite angles are equal,

Therefore equate both the angles.

3x-2=50-x

3x+x=50+2

4x=52

x=52/4

x=13

Now the two opposite angles are:

1. 3x-2

=3(13)-2

=39-2

=37°

2. 50-x

=50-13

=37°

Now, we found two angles of a parallelogram as 37°

Now, the third angle must be adjacent to these angles.

Let the third angle be 'x'.

Sum of adjacent angles is 180° in a parallelogram.

∴ 37+x=180°

x=180-37

x=143°

Now third angle is 143°

Fourth angle is also 143°(∵ opposite angles)

We found all the angles of a parallelogram, they are:

37°,37°,143°,143°

Hope it helps you!

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