two opposite angles of a parallelogram are (3x-2) and (50-X). Find the measure
of each angle of the parallelogram.
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Answer:
37°,37°,143° and 143°
Step-by-step explanation:
Given,
Two opposite angles of a parallelogram are 3x-2 and 50-x.
In a parallelogram opposite angles are equal,
Therefore equate both the angles.
3x-2=50-x
3x+x=50+2
4x=52
x=52/4
x=13
Now the two opposite angles are:
1. 3x-2
=3(13)-2
=39-2
=37°
2. 50-x
=50-13
=37°
Now, we found two angles of a parallelogram as 37°
Now, the third angle must be adjacent to these angles.
Let the third angle be 'x'.
Sum of adjacent angles is 180° in a parallelogram.
∴ 37+x=180°
x=180-37
x=143°
Now third angle is 143°
Fourth angle is also 143°(∵ opposite angles)
We found all the angles of a parallelogram, they are:
37°,37°,143°,143°
Hope it helps you!
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