Question

two opposite angles of a parallelogram are (3x - 2) and (63 - 2x).find all the angles of parallelogram

Answer 1

In a parallelgram opposite angles are equal
 
i.e..(3x-2)=(63-2x)
3x-2=63-2x
3x+2x=63+2
5x=65
x=65/5
x=13

substituting x =13 we get
3×13-2=63-2×13
37 = 37

so the angles are 37° , 180°-37°,37° and 180°-37°
i.e. 37°,143°,37°and 143°

Answer 2

Answer:

The angles are 37 and 143

Step-by-step explanation:

Property of parallelogram : In a parallelogram opposite angles are equal

 So,$(3x-2)=(63-2x)$

$3x-2=63-2x$

$3x+2x=63+2$

$5x=65$

$x=\frac{65}{5}$

$x=13$

(3x-2)=(3(13)-2)=37

Sum of adjacent angles of parallelogram is 180

So, 180-37 = 143

Hence the angles are 37 and 143