Math, asked by nehaarika, 3 months ago

Two opposite angles of a parallelogram are [3x-98]^0 and [50-x]^0.Find the measure of each angles.

Answers

Answered by rkcomp31
3

Answer:

1°,1°,179°,179°

Step-by-step explanation:

opposite angles of a parallelogram are equal

so 3x-98)^0= [50-x]^0=1

sso opposite angles are 1 each

now other oppoiste angles are eqal=x

so x+x+1+x1=360

2x+2=360

2x=358

x=179

Thus angles are :

1°,1°,179°,179°

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