Two opposite angles of parallelogram are 3 x minus 2 degree and 50 minus x degree find the measure of each angle of the parallelogram
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Answered by
13
Answer:(3x-2)°+(50-x)°=180°
Or, 3x-x+50°-2°=180°
Or,2x+48°=180°
Or, 2x=(180-48)°=132°
Or,x=66°
Therefore one angle is (3x-2)°=(3×66-2)°=196°
And,
Another angle is (50-x)°=-16°
Step-by-step explanation:
Answered by
4
Answer:
. In a parallelogram opposite angles are equal
3x-2 =50-x
3x+x=52
4x=52
x = 52/4=4=13 degree,
the angles are 13,167,13 & 167
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