two opposite angles of parallelogram are (3x-4) and (60-x). Find the measure of each angles of the parallelogram
Answers
3x+x=60+4
4x=64
x= 64÷4
x= 16
I hope it helped you.
Given,
Two opposite angles of a parallelogram are (3x-4) and (60-x).
To find,
The measure of each angle of the parallelogram.
Solution,
The measure of each angle of the parallelogram will be 44°, 44°, 126°, and 126°.
We can easily solve this problem by following the given steps.
We know in a parallelogram the opposite sides are parallel and of equal length. And the opposite angles are equal.
So, we have
(3x-4) = (60-x)
3x = 60+4-x ( Moving 4 from the left-hand side to the right-hand side will result in the change from the minus to plus.)
3x = 64-x
3x+x = 64 ( Moving x from the right-hand side to the left-hand side will result in the change from the minus to plus.)
4x = 64
x = 64/4
x = 16
Putting the value of x in each angle,
3x-4 = 3×16-4
48-4 = 44°
In a parallelogram, the sum of all the angles is 360°.
Let's take the third angle to be y°. ( The fourth angle will be equal to the third.)
44 + 44 + y + y = 360°
88 + 2y = 360°
2y = 360-88
2y = 272
y = 272/2
y = 126°
Hence, all the angles of the parallelogram are 44°, 44°, 126°, and 126°.