Math, asked by dhillon8755p3cog7, 1 year ago

two opposite angles of parallelogram are (3x-4) and (60-x). Find the measure of each angles of the parallelogram

Answers

Answered by Gitashree11
78
3x-4=60-x
3x+x=60+4
4x=64
x= 64÷4
x= 16
I hope it helped you.
Answered by HanitaHImesh
6

Given,

Two opposite angles of a parallelogram are (3x-4) and (60-x).

To find,

The measure of each angle of the parallelogram.

Solution,

The measure of each angle of the parallelogram will be 44°, 44°, 126°, and 126°.

We can easily solve this problem by following the given steps.

We know in a parallelogram the opposite sides are parallel and of equal length. And the opposite angles are equal.

So, we have

(3x-4) = (60-x)

3x = 60+4-x ( Moving 4 from the left-hand side to the right-hand side will result in the change from the minus to plus.)

3x = 64-x

3x+x = 64 ( Moving x from the right-hand side to the left-hand side will result in the change from the minus to plus.)

4x = 64

x = 64/4

x = 16

Putting the value of x in each angle,

3x-4 = 3×16-4

48-4 = 44°

In a parallelogram, the sum of all the angles is 360°.

Let's take the third angle to be y°. ( The fourth angle will be equal to the third.)

44 + 44 + y + y = 360°

88 + 2y = 360°

2y = 360-88

2y = 272

y = 272/2

y = 126°

Hence, all the angles of the parallelogram are 44°, 44°, 126°, and 126°.

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