two opposite corners of a square carry Q charge each and the other two opposite corners of the same square carry q charge each. if the resultant force on q is zero,how are Q and q related.
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Given: Two opposite corners of a square carry Q charge each and the other two opposite corners of the same square carry q charge each.
To find: How are Q and q related?
Solution:
- Now we have given two corners are having q charge and other two corners are having Q charge.
- Now, let the side of square be x, then its diagonal will be: x√2
- Now forces are:
F1 = F2 = kQq / x²
F3 = F4 = kqq (x√2)² = kq² / 2x²
- Now we know that F1 ⊥ F2, so resultant will be:
F = √F1² + F2² = F1√2 (as F1 and F2 are equal)
- Now net force on q is 0, so:
F1√2 = -F3
kQq√2 / x² = -kq² / 2x²
- Cancelling the common terms, we get:
q = -2√2Q
Answer:
So the relation between q and Q is q = -2√2Q
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