two opposite sides a b and DC of a cyclic quadrilateral ABCD intersect in e when produced prove that triangle e a d and ECB are similar
Answers
Answered by
18
In triangle aed and ecd
ae=ec (radius)
be=ed (radius)
angle aed=angle bec (v.o.a)
ae=ec (radius)
be=ed (radius)
angle aed=angle bec (v.o.a)
kaustubh123aa:
sorry I cant understand your answer.Can u explain with a diagram
i explain
but pls give a diagram also
first make a circlr and take four point on circle name ABCD and intersect in quadrilateral ABCD at E
Similar questions