Two pails contained a total of 21.8 liters of water. After 0.36 liters of water is poured from the small pail into the big pail, the amount of water in the big pail is 9 times that in the small pail. How much water was in each pail at first?
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Answer:
19.26 L
Step-by-step explanation:
Let water contained in small pail be X L
Then water contained in big pail =(21.8-X) L
Water in small pail after 0.36 L water poured out=X-0.36
Water in big pail after 0.36 L water poured in=21.8-X+0.36=22.16-X L
9(X-0.36)=22.16-X
9X—3.24=22.16-X
9X+X=22.16+3.24=25.4
X=25.4/10=2.54
Quantity of water in small pail at first=2.54 L
Quantity of water in small pail at first=21.8 - 2.54=19.26 L
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