Question

Two parallel and opposite forces each 4000 newton applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side find the angle of shear of the upper surface related to the lower surface the shear modulus for the metal is 80 gpa

Answer 1

Given Two parallel and opposite forces each 4000 newton applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side find the angle of shear of the upper surface related to the lower surface the shear modulus for the metal is 80 gpa

We are given

Force = 4000 N, metal L = 0.25 m , A = 0.0625 sq m. G = 8 x 10^10 N/m^2

Angle of shear = F / AG

                     = 4000 / 0.0625 x 8 x 10^10

                   = 8000 x 10 ^-10

                     = 8 x 10 ^- 7

We know that

 Δ L = Ф x L

     = 8 x 10 ^-7 x 0.25

Δ L = 2 x 10^-7 m