Two parallel chords of a circle lie on the same side of the centre of a circle. If the distance between
the chords is 1 cm and the lengths of the chords are 10 cm and 6 cm, find the radius of the circle.
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Answer:
di2=r^2-(CI/2) 2
di 2 = r^2-5^2. (i)
di^2 =r^2-25
d2^2 = r^2-9. (2)
subtract (I)-(2)
di^2-d2^2 = 16
di-d2=1. data
di +d2=16
solving 2 di=17
di= 8.5
d2=7.5
radius:
r =v7.5^2+5^2 = 9cm (appr:)
= V72.25 +25=v97.25=9.8cm.
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