Two parallel chords of lengths 30 cm and 16cm are drawn on the opposite sides of the centre of a circle of radius 17 cm. Find the distance between the chords
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Answer:23cm
Step-by-step explanation: consider triangle POA
OA=17cm, PA=AB/2=15cm
OA^2-PA^2=PO^2
17^2-15^2=PO^2
289-225=PO^2
64=PO^2
8cm=PO
NOW CONSIDER TRIANGLE DOS
DS=CD/2=8CM, OD=17CM
DO^2-DS^2=OS^2
17^2-8^2=OS^2
225=OS^2
15CM=OS
DISTANCE BETWEEN THE CHORDS = OS+PO
=15+8=23CM
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