Two parallel conductors carrying current of 4.0 A and 10.0 A are placed 2.5 cm apart in vacuum. The force per unit length between them is - (a) 6.4 x 10-5 N/m 6.4 x 10-2 Nm (b) (c) 4.6 x 10-4 N/m (d) 3.2 x 10-4 N/m 84102, 841152
Answers
Answer:
Two parallel conductors carrying a current of 4.0 A and 10.0 A are placed 2.5 cm apart in a vacuum. The force per unit length between the two conductors is
Explanation:
- From the Biot-Savart law, we know there will be a magnetic field due to current-carrying conductors, that magnetic field exerts a force on the conductor
- suppose that a conductor A with current and another conductor B carrying current are separated by a distance the force on a length of the conductor A due to conductor B is
- From Ampere's law, the magnetic field at the conductor B is
- so the force between the conductors
from the question, we have
current in conductor A
and that of conductor B is
the distance between the conductors
asked for force per unit length
value of
⇒
Given :
current in conductor 1 (i) = 4 A; current in conductor 2 (i) = 10 A; Distance between the conductors (d) = 2.5 cm = 2.5 x m
To Find :
The force per unit length between the current carrying conductors
Solution :
Force per unit length () =
= ×
= 32 x
= 3.2 x N/m
Therefore, The force per unit length between the conductors is 3.2 x N/m.
The correct option is (d).
Note -
- It is the mutual interaction.
- Parallel currents in same direction attract each other.
- Current in opposite direction repel each other.