Two parallel forces of magnitude 4 and 6 Newton are acting on a body placed at 4 m apart. Resultant force will be
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if the forces are in same direction, then the resultant force will be 10N if in opposite direction it will be 2 N.
Let us calculate the position of this force. This can be found by calculating the mean distance of the forces
I am taking 4N force as reference. so
weighted mean = ((0m)×4N + (4m)×6N)/(4N+6N)
=24/10 m = 2.4m from 4N force
Let us calculate the position of this force. This can be found by calculating the mean distance of the forces
I am taking 4N force as reference. so
weighted mean = ((0m)×4N + (4m)×6N)/(4N+6N)
=24/10 m = 2.4m from 4N force
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