two parallel plates are 5 cm apart and a potential difference of 60 v is set up between the two plates find the electric field intensity between the plates
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Answer:
Relation between potential difference and electric field:
E =-\frac{ \delta V }{\delta r}E=−
δr
δV
E = -V/r
E= -60/0.05
E = -1200 N/C
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