Math, asked by shonitdhiman9, 4 months ago

Two parallel sides DC and AB of a trapezium are 12 cm and 36 cm respectively.
if non parallel sides are each equal to 15 cm, find the area of trapezium​

Answers

Answered by Anonymous
6

Step-by-step explanation:

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Area of a trapezium= 1/2× sum of parallel sides× Height

To find the height, divide trapezium inta a parallelogram and triangle

The dimensions of the parallelogram will be 12 cm and 15 cm

Hence, traingle's base= 36-12= 24cm

Now apply Pythagoras's theorem after doing the triangle half

AC²= AB²+ BC²

15²= AB²+12²

AB²= 225-144

AB= 9CM= height

Area= 1/2× (12+36)× 9

1/2× 48×9

= 24× 9

= 216cm² is the correct answer

Hope it is helpful

Answered by Anonymous
3

answer

Step-by-step explanation:

Area of a trapezium= 1/2× sum of parallel sides× Height

To find the height, divide trapezium inta a parallelogram and triangle

The dimensions of the parallelogram will be 12 cm and 15 cm

Hence, traingle's base= 36-12= 24cm

Now apply Pythagoras's theorem after doing the triangle half

AC²= AB²+ BC²

15²= AB²+12²

AB²= 225-144

AB= 9CM= height

Area= 1/2× (12+36)× 9

1/2× 48×9

= 24× 9

= 216cm² is the correct answer

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