Math, asked by 012345nit, 11 months ago

Two parallel sides of a rectangle respectively lengthen at a rate of 2cm per second, while the other two parallel sides shorten such that the area of the rectangle is always 50cm^2. If at a time 't', the length of each lengthening side is 'x' , the length of each shortening side is 'y' and the perimeter of the rectangle is 'p', show that
dp/dx =2-100/x^2

Answers

Answered by amrita
0

Step-by-step explanation:

array.. give in short Yar. pls.

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