two parallel sides of a trapezium are 60 cm and 77 cm and the other sides are 25cm and 26 cm. Find the area of the trapezium
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Draw a line BC parallel to AD Draw a perpendicular line BE on DFABCD is a parallelogram.BC=AD=25cmCD=AB=60cmCF=77-CD=17cm
For Δ BCFperimeter of triangle=(25+26+17)/2=68/2=34By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)=√34(34-25)(34-26)(34-17)=204cm²
Now area of ΔBCF=1/2xbase x height=1/2 BExCF204cm²=1/2x BEx17BE=408/17=24cm
Area of Trapezium =1/2(AB+DF)xBE=1/2(60+77)x24=1644cm²
Draw a line BC parallel to AD Draw a perpendicular line BE on DFABCD is a parallelogram.BC=AD=25cmCD=AB=60cmCF=77-CD=17cm
For Δ BCFperimeter of triangle=(25+26+17)/2=68/2=34By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)=√34(34-25)(34-26)(34-17)=204cm²
Now area of ΔBCF=1/2xbase x height=1/2 BExCF204cm²=1/2x BEx17BE=408/17=24cm
Area of Trapezium =1/2(AB+DF)xBE=1/2(60+77)x24=1644cm²
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area of trapezium is 1/2*h*(a+b
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