Question

Two parallel sides of a trapezium are of length 20cm and 26cm, and the

distance between them is 10cm , Area of trapezium is ​

Answer 1

Answer: 230cm²

Step-by-step explanation: Area of trapezium= 1/2* sum of parallel sides * height

Distance between them is height

1/2*46cm*10cm

= 230cm²

Answer 2

Formula :

Area of trapezium : $a + b \div 2 \times h$

Given :

$a(base) = 20 \: cm$

$b(base) = 26 \:c m$

$h(height) = 10 \: cm \:$

$area = ?$

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$area = a + b \div 2 \times h$

$= 20 + 26 \div 2 \times 10$

$= 46 \times 5$

$= 230 \: cm ^{2}$

So , Area of trapezium is

$230 \: cm ^{2}$