Two parallel sides of an isosceles trapezium are 10 cm and 20 cm and its non-parallel sides are each equal to
13 cm. Find the area of the trapezium.
Answers
Answer:
Answer:180cm^2
Answer:180cm^2Step-by-step explanation:
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm difference
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its height
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theorem
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^2
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium1/2×( Sum of parallel sides)×h
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium1/2×( Sum of parallel sides)×h1/2×(10+20)×12
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium1/2×( Sum of parallel sides)×h1/2×(10+20)×121/2×30×12
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium1/2×( Sum of parallel sides)×h1/2×(10+20)×121/2×30×1230×6
Answer:180cm^2Step-by-step explanation:Its parallel sides =10 and 20So they will have both sides 5cm differenceWe will have to find its heightBy Pythagorean theoremH^2=P^2+b^213^2=p^2+5^2169=p^2 +25p^2=169-25p^2=144P= √144P=12Area of a trapezium1/2×( Sum of parallel sides)×h1/2×(10+20)×121/2×30×1230×6180cm^2