Question

Two parallel sides of an isosceles trapezium are 10 cm and 20 cm and its non parallel sides are each equal to 13 cm. Find the area of the trapezium.​

Answer 1

Step-by-step explanation:

n a trapezium ABCD, where AB=20cm and CD=10 cm are two parallel sides, and the non parallel sides are 13cm each .

Also AB=AE+EF+FB=5cm+10cm+5cm=20cm

You can use the Pythagorean theorem to find the height of the trapezium. Because this is an isosceles trapezium, the difference between the two parallel sides must be split equally. This creates two right triangles with one leg 5cm and the hypotenuse of 13 cm. the other leg is √(13²- 5²) = √(169 - 25) = √(144) = 12 cm.

The area of a trapezium is A= [(b₁+b₂)h]/2

Plug in the values and evaluate: A = [(20+10)12]/2 => A = [30•12]/2 => A = 360/2 => Area = 180 cm²

hence the area of trapezium is 180cm^2

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