Question

Two parallel sides of an isosceles trapezium are 6 cm and 14 cm respectively.if the length of each non-parallel side is 5 cm, find the area of the
trapezium.

Answer 1

a and b are the parallel sides..

$A = \frac{a+b}{2} h\\A = \frac{6 cm+14cm}{2} 5cm\\A= \frac{20cm}{2} 5cm\\A=10cm(5cm)\\A=50cm^2$

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Answer 2

area of a trapezium = 1/2h (a + b)
1/2 × 3 (6 + 14)
1/2 × 3 (20)
1/2 x 60
30 cm2