Question

Two parallel slits 1 millimeter apart are placed 1 meter away from screen. What is the fringe separation due to interference effect, when a beam of wavelength 500 nanometer is incident on them?

Answer 1

Answer: $\beta = 0.5\ mm$

Explanation:

Given that,

Distance between two slits d = 1 mm

Distance between slits and screen D = 1 m

Wave length = 500 nm

We know that,

The fringe separation is

$\beta = \dfrac{\lambda D}{d}$

$\beta = \dfrac{500\times10^{-9}m \times1\ m}{1\times10^{-3}\ m}$

$\beta = 0.5\ mm$

Hence, this is the required solution.