two particle 1 and 2 start moving simultaneously at equal to zero at a particle one moves along a diameter and particle two moves along the circumference of a circle if two particle 1 and 2 reach be simultaneously at the equal to zero then find the ratio of the magnitude of average velocity is and that of the average speed of the particle 1 and 2
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Answer:
2NH
4
Cl+Ca(OH)
2
→CaCl
2
+2H
2
O+2NH
3
53.5 gm of NH
4
Cl produces 17g of ammonia
So 32.6 gm will give 17×
53.5
32.6
=10.36 gm NH
3
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