Question

two particle A and Bof mass 10g and 20g respectively fall vertically .at a given time , the speed of particle A is 12m/s and that of B is 15m/s.find the total linear momentum of the system of the two particles

Answer 1

MV = m1v1 + m2v2

= 0.02 ( 15 ) + 0.01 ( 12 )

= 0.3 + 0.12

= 0.15 kg m/s

Hope it helps!

Answer 2

Mass of A = 10 g =  = 0.01 kg

Velocity of A = 12 m/s

Mass of B = 20 g =  = 0.02 kg

Velocity of B = 15 m/s

We know that :

Momentum of A = 0.01 × 12 = 0.12 kgm/s

Momentum of B = 0.02 × 15 = 0.3 kgm/s

Total Momentum = 0.12 kgm/s + 0.3 kgm/s

=》 0.42 kgm/s