Question

Two particle of equal mass m and charge q are placed at a distance of 16 cm.. They do note experience any force.Find the value of q/m

Answer 1

Answer:

(G/k)^1/2 where G is gravitational constant and K is Coulomb Constant. 2) But, there will be attractive force due to Attraction between masses by Gravitational force due to other mass m. And There will be repulsive force due to like charges repel each other.

Explanation:

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Answer 2

Answer:

Final Answer :

(G/k)^1/2 where G is gravitational constant and K is Coulomb Constant.

Steps:

1) Since, particle is in horizontal frame, so there will not be any effect from Gravitation force due to earthin Horizontal direction

2) But, there will be attractive force due to Attraction between masses by Gravitational force due to other mass m.

And There will be repulsive force due to like charges repel each other.

3) Since, system is in equilibrium.

Therefore. Net Force along Horizontal direction us 0 .

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