Question

Two particles A and B are moving with the same velocity but wavelength of A is found to be double than that of B. What do you conclude?

Answer 1

Hi,

Use this formula this help you, Momemtum=h/wavelength

P=h/lambda

Wavelength of the particle A is P'a'

And the momentum of the particle B is P'b'

Relation between P'a' and P'b'

P'b'=P'a'/2

Wavelength of B ( lambda)= h/P'b'

Answer 2

Answer:

Momemtum=h/wavelength

P=h/lambda

Wavelength of the particle A is P'a'

And the momentum of the particle B is P'b'

Relation between P'a' and P'b'

P'b'=P'a'/2

Wavelength of B ( lambda)= h/P'b'