Math, asked by ayandey7858, 11 months ago

two particles A and B are projected along different directions from the same point P on the ground with the same velocity of 70 M per second in the same vertical plane the hit the ground at the same point Q such that PQ is equals to 480m. Then:- [g=9.8m/s²]
(A)Ratio of their times of flight if 4:5
(B)Ratio of their maximum heights is 9:16
(C)Ratio of their minimum speeds during flights is 4:3
(D)The bisector of the angle between their directions of projection makes 45° with horizontal

Answers

Answered by amitnrw
23

Answer:

Step-by-step explanation:

Let say angle are α & β

Horizontal Speed = 70Cosα  & 70Cosβ

Vertical Speed = 70Sinα  & 70Sinβ

time to reach Peak Using V = U + aT

=> T = 70Sinα/g  & 70Sinβ/g

Time of Flight = 2*70Sinα/g  & 2*70Sinβ/g

Horizontal Distance = 70Cosα*2*70Sinα/g   & 70Cosβ*2*70Sinβ/g

= 1000CosαSinα   & 1000CosβSinβ  = 480

=> CosαSinα  = CosβSinβ = 0.48

=> Sin2α = Sin2β = 0.96

=> 2α & 2β  = 73.74   & 106.26

=> α & β = 36.87°   & 53.13°

Sinα = 0.6  & Sinβ = 0.8

or Same can be solved

{Sin²α + Cos²α = 1   SinαCosα = 0.48

(Sinα + Cosα)² - 2SinαCosα = 1  => (Sinα + Cosα)²  = 1.96

=> Sinα + Cosα = 1.4

(Sinα - Cosα)² +2SinαCosα = 1  => (Sinα - Cosα)²  = 0.04

=> Sinα - Cosα = 0.2

Adding Both Sinα = 0.8 Cosα = 0.6  }

=> The bisector of the angle between their directions of projection makes 45° with horizontal

Ratio of their times of flight = Sinα/Sinβ  =  0.6/0.8  =  3/4  => 3:4

Max height using V² -U² = 2aS  => Height =  (70Sinα)²/2*9.8  & (70Sinβ)²/2*9.8

=> S = 90   & 160   Ratio = 9:16

Minimum Speed will be when Vertical Velocity = 0

Only Horizontal Velocity Exists

=> 70Cosα & 70Cosβ  =>  56  & 42   =>  4 : 3

Ratio of their minimum speeds during flights is 4:3

Answered by HimanshiKankane
9

Step-by-step explanation:

The bisector of the angle between their directions of projection makes 45° with horizontal

Ratio of their times of flight = Sinα/Sinβ  =  0.6/0.8  =  3/4  => 3:4

Max height using V² -U² = 2aS  => Height =  (70Sinα)²/2*9.8  & (70Sinβ)²/2*9.8

=> S = 90   & 160   Ratio = 9:16

Minimum Speed will be when Vertical Velocity = 0

Only Horizontal Velocity Exists

=> 70Cosα & 70Cosβ  =>  56  & 42   =>  4 : 3

Ratio of their minimum speeds during flights is 4:3

Happy to help!

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