Question

Two particles A and B having positions rA = (3i+5j)m and rB = (-5i-3j)m are moving with velocity vA = (4i+3j)m/s and vB = (8i+aj)m/s. If they collide after 2s, the value of a is
(1) 2 (2) 8
(3) 7 (4) 9

Answer 1

Answer:

Let us consider the values as following:

r

1

=(3i+5j)m

r

2

=(−5i+3j)m

v

1

=(4i−4j)m/s

andletv

2

be=(−ai−3j)m/s

t=2sec

If two particles collides after time "t" they travel equal distance.

r

1

+v

1

t=r

2

+v

2

t

(3i+5j)+(4i−4j)×2=−5i+3j+(−ai−3j)2

onsolvingweget,

3i+8i+5j−8j=−5i+3j−2ai−6i

11i+5i−3j=−2ai−3j

16i=−2ai

a=

2

−16

=−8m/s

2

Explanation:

please mark my answer as brainliest

Answer 2

Answer:

a= -8m/s² 

Explanation:

In this question, Second Equation of Motion is to be used and also in this case the acceleration is zero, a=0

two objects collide when their position vector is same.

Also, I have used s instead of r.

Now, You see, This Question is Wrong, Two objects moving under given conditions will never collide.

But Let's just say that you have misread this question.

Now The Question can be rectified only if value of v₂ is

             v₂= (-ai - 3j)

Then The answer would be a= -8m/s²