Question

Two particles A and B, move with constant velocities, A with velocity VA = 3i + 4j and B with velocity vo = xi + 2j At the initial moment their positions are (20i + Oj) are (100i + 20j). If the two particles collide then value of x is​

Answer 1

Explanation:

Let us consider the values as following:

r

1

=(3i+5j)m

r

2

=(−5i+3j)m

v

1

=(4i−4j)m/s

andletv

2

be=(−ai−3j)m/s

t=2sec

If two particles collides after time "t" they travel equal distance.

r

1

+v

1

t=r

2

+v

2

t

(3i+5j)+(4i−4j)×2=−5i+3j+(−ai−3j)2

onsolvingweget,

3i+8i+5j−8j=−5i+3j−2ai−6i

11i+5i−3j=−2ai−3j

16i=−2ai

a= −16/2

=−8m/s²

Answer 2

Answer:

noo

Explanation:

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