Two particles A and B, move with constant velocities, A with velocity VA = 3i + 4j and B with velocity vo = xi + 2j At the initial moment their positions are (20i + Oj) are (100i + 20j). If the two particles collide then value of x is
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0
Explanation:
Let us consider the values as following:
r
1
=(3i+5j)m
r
2
=(−5i+3j)m
v
1
=(4i−4j)m/s
andletv
2
be=(−ai−3j)m/s
t=2sec
If two particles collides after time "t" they travel equal distance.
r
1
+v
1
t=r
2
+v
2
t
(3i+5j)+(4i−4j)×2=−5i+3j+(−ai−3j)2
onsolvingweget,
3i+8i+5j−8j=−5i+3j−2ai−6i
11i+5i−3j=−2ai−3j
16i=−2ai
a= −16/2
=−8m/s²
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Answer:
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Explanation:
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