Two particles are located at r=3i^+7j^ and r=-2i^+3j^.find the displacement b/w two particles (6.4,219°from the x-axis)
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Displacement = r2 - r1 = (-2 - 3)i + (3 - 7)j = -5i - 4j
Displacement (in magnitude) = √(-5^2 + -4^2) =√(41) = 6.4
Angle---
tan θ = -4/-5 = 219°
Displacement (in magnitude) = √(-5^2 + -4^2) =√(41) = 6.4
Angle---
tan θ = -4/-5 = 219°
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