Question

Two particles are moving along a horizontal plane as shown in top view). At t = 0, separation between them is 100/2 m. They will be at minimum separation at t = AY iB 37° 50 m/s 1002 m 38. -X 10 m/s 5 5V2 (1) (2) S 2 4 (3) 5 S 12 (4) 5s​

Answer 1

Trick for solving minimum seperation:

• Assume one of the particle at rest.
• give all the relative velocity to other particle.
• Now draw the perpendicular from Rest(B) to moving line of A. That perpendicular distance will be the minimum separation between them.
• time = min sep/relative velocity.

See the attachment for solution!

★ (2) is correct.

Answer 2

Explanation:

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Trick for solving minimum seperation:

Assume one of the particle at rest.

give all the relative velocity to other particle.

Now draw the perpendicular from Rest(B) to moving line of A. That perpendicular distance will be the minimum separation between them.

time = min sep/relative velocity.

See the attachment for solution!

★ (2) is correct.

$\pink{\boxed{I \:Hope\: it's \:Helpful}}$

${\sf{\bf{\blue{@Muskanjoshi14࿐}}}}$