Math, asked by AnmolBalwal, 1 year ago

Two particles are moving with a constant speed v such that they are always at a constant distance d apart and their velocities are always equal and opposite. After what time they return to their initial positions?


please answer its urgent.......

Answers

Answered by pankaj12je
15
Hey there !!!!!

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Two particles are moving with constant speed "v" and they are always at a constant distance.

This is possible only when the particles move in a circular path wrt to each other.

Time taken to return to their initial positions = Total distance /velocity

As the particles are moving in a circular path distance covered is equal to circumference of the circle.If "r" is radius of circular path

  distance= 2*π*r   

  Time taken = 2πr/v

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Hope this helped you...............

AnmolBalwal: thx
AnmolBalwal: thx
pankaj12je: wc :)
Answered by saka82411
11
Hi friend,

Myself saka here to help you,

Given clues,

Distance= same
velocity = differs

To find:-

Time period=?

From the given clues we can concluded that distance is same the particle . Only the velocity is different.

So the given particle must be in a circle where the distance (:-radius) same .
Only the velocity is different.

We know that
velocity=distance/time

:- time taken=DISTANCE/ VELOCITY

The radius is same so

Radius (:- distance) of the circle= 2×π×r

Time period= 2×π×r/v.

Hope this helps you





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