Question

two particles are released for same height at t=0 and t=2 seconds respectively. find he distance between both the particles at t=4​

Answer 1

Given info : two particles are released for same height at t = 0 sec and t = 2 seconds respectively.

To find : the distance between both particles at t = 4sec

Solution : case 1 : first particle released from a height h at t = 0,

So after 4 sec ,

distance covered by it, S = ut + 1/2 at²

= 0 × 4 + 1/2 × 10 × (4)²

= 80 m

Case 2 : 2nd particle released 2 sec after the first particle, so distance covered in (4 - 2) sec by 2nd particle is S' = 0 × 2 + 1/2 × 10 × (2)² = 20 m

So the distance between both the particles at t = 4 sec is (80 - 20) = 60 m