Question

Two particles are shown in the figure. At t = 0 a constant
force F=6 N starts acting on the 3 kg man. Find the velocity
of the centre of mass of these particles at t= 5 s.
2 kg
3 kg
F=6N​

Answer 1

Answer:

The velocity of the centre of mass of particles= 10 m/s

Explanation:

Force, F= 6N

Mass of the man, m= 3kg

We know that

F = m × a

=>6 = 3 × a

=>a = 2m/s²

At t= 0, initial velocity, u= 0m/s

At t= 5, final Velocity, v= ?

We know that,

a = v - u/t

=>2 = v - 0/5

=>2 = v/5

=>v = 10m/s