Question

Two particles move in a uniform gravitational field
with acceleration g. At the initial moment, the
particles were located at one point and moved with
velocities v = 3 m/s and v2 = 4 m/s horizontally in
opposite directions. The distance between the
particles at the moment, when their velocity vectors
become mutually perpendicular, is​

Answer 1

Answer:(v1 + v2)t = (v1 + v2)*under root v1*v2/g