Two particles of equal mass go round a circle of radius R under the action of their mutual gravitational attraction.Find the speed of each particle.
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let m are the mases of each particles
if they attract with mutual gravitational gravitational force then,
force act between them is
F = GM²/(2R)²= GM²/4R²
each body attracted by GM²/4r² , hence, must centrifugal force required to balance each of this force
e.g F <------- >Centrifugal
F = centrifugal force
but we know, centrifugal force = mv²/R
so,
F = mv²/R
Gm²/4R² =mv²/R
Gm/4R =v²
v =√(Gm/4R)
if they attract with mutual gravitational gravitational force then,
force act between them is
F = GM²/(2R)²= GM²/4R²
each body attracted by GM²/4r² , hence, must centrifugal force required to balance each of this force
e.g F <------- >Centrifugal
F = centrifugal force
but we know, centrifugal force = mv²/R
so,
F = mv²/R
Gm²/4R² =mv²/R
Gm/4R =v²
v =√(Gm/4R)
abhi178:
i am not sure this is correct or not !!!
but i hope this is correct
can you see answer ?
Its the correct answer
Thanks^_^
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