two particles of equal mass m go around a circle of radius R under the action of their mutual gravitational attraction . the speed v of each particle is
1)1/2*(Gm/R)1/2
2)1/2R*(1/Gm)1/2
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sorry I don't know the answer please don't feel bad
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Fg=Fcentrepital so GMm/r^2=MV^2/r then after solve it v^2=GM/r
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