Question

Two Particles of masses 1 kg and 2 kg are located at x=0 and x=3m.Find the position of their center of mass​

Answer 1

Explanation:

use formula CM=m1x1+m2x2÷m1+m2

$cm = 1 \times 0 + 2 \times 3 \div 3 \\ cm = 6 \div 3 \\ cm = 2$

Answer 2

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$\blacksquare$Since both the particles lies on the x-axis,the COM will also lie on x-axis.

Now

Let the COM is located at x=x,then

r1=distance of COM from he particles of mass 1kg=x

and

r2 =distance of COM from the particle of the mad 2kg=(3-x)

$\implies$ Using $\frac{r1}{r2} = \frac {m2}{m1}$

$\implies$$\large \frac{x}{3 - x} = \frac{2}{1}$

$\implies$x=2m

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