Question

Two particles of masses m and 1 m2 initially at rest start moving towards each other under their mutual

force of attraction. The speed of the centre of mass at any time t, when they are at a distance r apart, is?​

Answer 1

Answer:

Zero

Explanation:

Lemme explain ya,okay?

Fext = 0

Pi = Pf

so,.

0 = m1v1 + m2v2

so, m1v1 - m2v2

now,

Vcm = m1v1 + m2v2 / m1 + m2

as above I have shown m1v1 + m2v2 = 0

and m1v1 - m2v2

can't we write m1v1 - m2v2 / m1 + m2

of course we can!

so m1v1 - m2v2 / m1 +m2 = 0

smjh aayaa!! ??? ummm..

Answer 2

Answer:

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IN ATTACHMENT

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