Question

Two particles of masses M and 4M are
released from a distance 10 metres from
each other. Find the point of collision from
smaller particle.

Question Type: Single Correct Type
1) 8 metres
2) 2 metres
3) 5 metres

4.)6 metres​

Answer 1

Answer:

They will collide at centre of mass.

x= M(0)+4M(10)

_________

M+4M

x= 8 metres

Answer 2

Answer:

The point of collision from a smaller particle is 8 meters i.e.option(1).

Explanation:

We will use the following formula to solve this question,

$x=\frac{m_1r_1+m_2r_2}{m_1+m_2}$       (1)

Where,

x=point where the two particles will collide

r₁,r₂=respective position of particles

m₁,m₂=respective masses of particles

From the question we have,

m₁=M

m₂=4M

r₁=0

r₂=10m

By substituting the values in equation (1) we get;

$x=\frac{M\times 0+4M\times 10}{M+4M}$

$x=\frac{40M}{5M}$

$x=8m$

Hence,  the point of collision from a smaller particle is 8 meters i.e.option(1).