Two particles of masses m and M (M > m ) are connected by
a cord that passes over a massless, frictionless pulley. The
tension T in the string and the acceleration a of the particles
is
(a) T = 2mM/(M - m) g ;a = Mm/(M + m) g
(b) T = 2mM/(M + m) g; a = (M - m/M + m) g
(c) T = (m - M/M + m) g;a = (Mm/M + m) g
(d) T = (mM/M + m) g;a = (2Mm/M + m) g
Answers
Answered by
2
Answer:
T = 2mM/(M - m) g ;a = Mm/(M + m) g
(b) T = 2mM/(M + m) g; a = (M - m/M + m) g
(c) T = (m - M/M + m) g;a = (Mm/M + m) g
(d) T = (mM/M + m) g;a = (2Mm/M + m) g
Explanation:
hope you understand mate
Answered by
16
Explanation:
(a) T = 2mM/(M - m) g ;a = Mm/(M + m) g
(b) T = 2mM/(M + m) g; a = (M - m/M + m) g
(c) T = (m - M/M + m) g;a = (Mm/M + m) g
(d) T = (mM/M + m) g;a = (2Mm/M + m) g
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