Two particles one of mass m and the other of mass 2m are projected horizontally towards each other from the same level above the ground with velocities and respectively. They collide in air and stick to each other. The distance from a, where the combined mass finally land is
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Hii mate,
You have missed some data.
◆ Answer- 40 m
◆ Explanation-
# Given-
D = 60 m
v1 = 10 m/s
v2 = 5 m/s
# Solution-
Time taken by masses to collide is-
time = distance / velocity
t = D / (v1+v2)
t = 60 / (10+5)
t = 4 s
Distance covered by mass m in 4 s is-
distance = velocity × time
s = 10 × 4
s = 40 m
Therefore, combined masses will be 40 m from point A.
Hope this is useful...
You have missed some data.
◆ Answer- 40 m
◆ Explanation-
# Given-
D = 60 m
v1 = 10 m/s
v2 = 5 m/s
# Solution-
Time taken by masses to collide is-
time = distance / velocity
t = D / (v1+v2)
t = 60 / (10+5)
t = 4 s
Distance covered by mass m in 4 s is-
distance = velocity × time
s = 10 × 4
s = 40 m
Therefore, combined masses will be 40 m from point A.
Hope this is useful...
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