Question

Upon passing 0.01 mole HCL gas through 100 ml of 0.05 M formic acid solution determine change in pH of solution . Ka=1.8x10^-4

Answer 1

Upon passing 0.01 mole HCL gas through 100 ml of 0.05 M formic acid solution determine change in pH of solution . Ka=1.8x10^-4

So here what you should note is that passing HCl gas only introduces or adds more H+ ions in the formic acid.

Thus new concentration of formic acid is 0.05 + 0.01 = 0.06 M

Degree of ionization is = √ka/C

                                       = √1.8 x 10^-4/0.05

                                       = 0.06

Equillibrium [H+] = 0.05 x 0.06= 0.003 M

then pH = -log 0.003

              Initial pH= 2.5

after addition of 0.01 M HCl, the new [H+] = 0.06

equilibrium concentration = 0.06 x 0.06= 0.0036 M

then final pH = -log 0.0036

               pH = 2.4

change in pH= 2.5 - 2.4 = 0.1

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Answer 2

Answer:change in pH=-1, 52

Explanation: